What volume of hydrogen will be released during the interaction of 20 g of zinc containing 2%

What volume of hydrogen will be released during the interaction of 20 g of zinc containing 2% impurities with a solution of hydrochloric acid weighing 200 g with a mass fraction of hydrochloric acid of 36%?

The chemical reaction is described by the following equation:

Zn + 2HCl → ZnCl2 + H2;

The reaction requires double the amount of acid.

Let’s find the molar amounts of reagents.

Let’s determine the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 20 x 0.98 / 65 = 0.302 mol;

Let’s find the chemical amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 200 x 0.36 / 36.5 = 1.973 mol;

The acid is taken in large excess.

Let’s find the volume of released hydrogen.

V H2 = 22.4 x 0.302 = 6.765 liters;