What volume of hydrogen will be released during the interaction of 260 g of Zn with hydrochloric acid?

Given:

m (Zn) = 260 g;

To find:

V (H2) -?

Decision:

1) We compose the reaction equation characteristic of the problem condition:

Zn + 2HCl = ZnCl2 + H2;

2) Find the amount of zinc contained in 260 grams of metal:

n (Zn) = m: M = 260 g: 65 g / mol = 4 mol;

3) We compose a logical expression:

if 1 mole of Zn gives 1 mole of H2,

then 4 mol of Zn will give x mol of H2,

then x = 4 mol.

4) Find the volume of hydrogen gas released during the reaction:

V (H2) = n * Vm = 4 mol * 22.4 L / mol = 89.6 L;

Answer: V (H2) = 89.6 liters.