What volume of hydrogen will be released during the interaction of 5 mol of zinc with chloride acid?

univerkov | January 17, 2021 | education

Given:
n (Zn) = 5 mol
To find:
V (H2)
Decision:
Zn + 2HCl = ZnCl2 + H2
n (Zn): n (H2) = 1: 1
n (H2) = 5 mol
V (H2) = n * Vm = 5 mol * 22.4 L / mol = 112 L
Answer: 112 l

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.