What volume of hydrogen will be released during the interaction of 6.5 g zinc with hydrochloric acid solution?

The interaction of zinc with hydrogen chloride occurs in accordance with the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

When 1 mole of metal dissolves, 1 mole of hydrogen gas is released.

Let’s calculate the amount of substance contained in a sample of 6.5 grams of metal.

To do this, we find the ratio of its weight to molar mass.

N Zn = 6.5 / 65 = 0.1 mol;

The same amount of hydrogen will be released during this interaction.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.1 x 22.4 = 2.24 liters;