What volume of hydrogen will be released during the interaction of ethylene glycol C2H6O2

What volume of hydrogen will be released during the interaction of ethylene glycol C2H6O2 weighing 8 grams with sodium weighing 2.3 g?

Given:
m (C2H4 (OH) 2) = 8 g
m (Na) = 2.3 g

To find:
V (H2) -?

1) Write the equation of a chemical reaction:
C2H4 (OH) 2 + 2Na => C2H4 (ONa) 2 + H2 ↑;
2) Calculate the amount of ethylene glycol substance:
n (C2H4 (OH) 2) = m / M = 8/62 = 0.13 mol;
3) Calculate the amount of sodium substance:
n (Na) = m / M = 2.3 / 23 = 0.1 mol;
4) Determine the amount of hydrogen substance:
n (H2) = n (Na) / 2 = 0.1 / 2 = 0.05 mol;
5) Calculate the volume of hydrogen:
V (H2) = n * Vm = 0.05 * 22.4 = 1.12 liters.

Answer: The volume of H2 is 1.12 liters.