What volume of hydrogen will be released when 0.3 mol of acetic acid interacts with an excess of magnesium?

We will carry out the solution, we will compose the reaction equation:
2СН3СООН + Mg = (CH3COO) 2Mg + H2 – substitution reaction, magnesium acetate and hydrogen are released;
Let’s make calculations using the formulas:
M (CH3COOH) = 12 * 2 + 1 * 4 + 16 * 2 = 60 g / mol;
Y (CH3COOH) = 0.3 mol;
Based on the data from the equation, we will compose the proportion:
0.3 mol (CH3COOH) – X mol (H2);
-2 mol -1 mol hence, X mol (H2) = 0.3 * 1/2 = 0.15 mol;
Let’s calculate the volume of hydrogen using Avogadro’s law:
V (H2) = 0.15 * 22.4 = 3.36 liters.
Answer: during the reaction, 3.36 liters of hydrogen is released.