What volume of hydrogen will be released when 0.5 mol of hydrochloric acid interacts with zinc?

Zinc interacts with hydrochloric acid to release hydrogen.

Zn + 2HCl → ZnCl2 + H2;

For the reaction to proceed completely, double the amount of acid is required.

According to the condition of the problem, the chemical amount of zinc is:

N Zn = 0.5 mol;

If we multiply the amount of hydrogen by the volume of 1 mole of gas, then we get its volume:

V H2 = 22.4 x 0.5 = 11.2 liters;