What volume of hydrogen will be released when 1 kg of zinc is dissolved in an excess of acid?
September 28, 2021 | education
| The scheme for dissolving zinc in hydrochloric acid is as follows:
Zn + 2HCl → ZnCl2 + H2;
One zinc molecule requires 2 acid molecules.
Let’s find the molar amount of zinc.
M Zn = 65 grams / mol;
N Zn = 1,000/65 = 15.385 mol;
The same amount of hydrogen will be synthesized. Let’s find its volume.
V H2 = 22.4 x 15.385 = 344.624 liters;
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