What volume of hydrogen will be released when 1 kg of zinc is dissolved in an excess of acid?

The scheme for dissolving zinc in hydrochloric acid is as follows:

Zn + 2HCl → ZnCl2 + H2;

One zinc molecule requires 2 acid molecules.

Let’s find the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 1,000/65 = 15.385 mol;

The same amount of hydrogen will be synthesized. Let’s find its volume.

V H2 = 22.4 x 15.385 = 344.624 liters;

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