What volume of hydrogen will be released when 10 g of zinc reacts with an excess of sulfuric acid solution?

Zinc metal reacts with sulfuric acid to release hydrogen gas and form zinc sulfate. The reaction is described by the following equation:

Zn + H2SO4 = ZnSO4 + H2;

1 mole of metal reacts with 1 mole of acid. This synthesizes 1 mol of salt and 1 mol of hydrogen.

Let’s calculate the amount of zinc.

M Zn = 65 grams / mol;

N Zn = 10/65 = 0.154 mol;

During the reaction, 0.154 mol of hydrogen will be synthesized. Let’s calculate its volume.

To do this, multiply the amount of substance by the volume of 1 mole of gas.

V H2 = 0.154 x 22.4 = 3.45 liters;