What volume of hydrogen will be released when 11.7 g of zinc is added to a solution containing 30 g of sulfuric acid?

This chemical reaction converts zinc metal to zinc sulfate. Zinc is a divalent metal. Therefore, during the reaction, it interacts with an equal amount of sulfuric acid. In this case, the same chemical amount of zinc sulfate is synthesized. The reaction is described by the following chemical reaction equation:

Zn + H2SO4 = ZnSO4 + H2;

Let’s calculate the molar amount of sulfuric acid. To do this, we divide its weight by the mass of 1 mole of the substance.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 30/98 = 0.306 mol;

Let’s determine the chemical amount of zinc. To do this, we divide its weight by the mass of 1 mole of metal.

N Zn = 11.7 / 65 = 0.18 mol;

With this amount of zinc, 0.18 mol of acid will react. This will synthesize 0.18 mol of hydrogen. Let’s calculate its volume. For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters).

V H2 = 0.18 x 22.4 = 4.032 liters;