What volume of hydrogen will be released when 120 g of 15% sulfuric acid solution interacts with zinc?

First, we write down the reaction equations for this problem.

Zn + H2SO4 = ZnSO4 + H2.

Let’s calculate the mass of sulfuric acid. We use the following formula.

W = m r.v / m r-ra * 100%.

m (H2SO4) = 120 * 0.15 = 18 g.

Let’s determine the molar mass of sulfuric acid and hydrogen.

M (H2SO4) = 1 * 2 + 32 + 16 * 4 = 98 g / mol.

M (H2) = 1 * 2 = 2 g / mol.

Let us determine the mass of hydrogen according to the reaction equation.

18 g sulfuric acid – x g hydrogen.

98 g / mol – 2 g / mol.

X = 0.37 g.

V / Vm = m / M.

V = 22.4 * 0.37: 2 = 2.06 l.

Answer: 2.06 liters.