What volume of hydrogen will be released when 13 g of zinc react with a solution containing 7.3 g of hydrogen chloride?

If zinc is mixed with hydrochloric acid, hydrogen and zinc chloride will be released.

This requires a double molar amount of acid.

Zn + 2HCl → ZnCl2 + H2;

Let’s find the available molar amounts of substances:

Let’s calculate the chemical amount of zinc.

M Zn = 65 grams / mol;

N Zn = 13/65 = 0.2 mol;

Let’s determine the molar amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 7.3 / 36.5 = 0.2 mol;

From 0.2 mol of acid, it is possible to obtain 0.1 mol of hydrogen.

Let’s find its volume:

V H2 = 22.4 x 0.1 = 2.24 liters;