What volume of hydrogen will be released when 20 g of hydrochloric acid interacts with 34 g of copper?

The reaction of copper with hydrochloric acid is described by the following chemical reaction equation.

Cu + 2HCl = CuCl2 + H2;

One mole of copper reacts with two moles of hydrochloric acid. This produces one mole of hydrogen. Determine the amount of substance contained in 34 grams of copper and 20 grams of 36.5% hydrochloric acid.

M Cu = 64 grams / mol;

N Cu = 34/64 = 0.531 mol;

M HCl = 1 + 35.5 = 36.5 grams / mol;

m HCl = 20 grams;

N HCl = 20 / 36.5 = 0.548 mol;

0.548 / 2 = 0.274 mol of copper will react with 0.548 mol of hydrochloric acid. In this case, 0.548 / 2 = 0.274 mol of hydrogen is formed.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of hydrogen.

V H2 = 0.274 x 22.4 = 6.138 liters;