What volume of hydrogen will be released when 3 mol of CA interacts with water?

1. Let’s write the equation of interaction of calcium with water:

Ca + 2H2O = Ca (OH) 2 + H2 ↑;

2.according to the reaction equation, the stoichiometric amounts of calcium and hydrogen are equal, we determine the chemical amount of released hydrogen:

n (H2) = n (Ca) = 3 mol;

3.Calculate the volume of hydrogen:

V (H2) = n (H2) * Vm = 3 * 22.4 = 67.2 liters.

Answer: 67.2 liters.