What volume of hydrogen will be released when 5.4 g of aluminum is exposed to a sulfuric acid solution

What volume of hydrogen will be released when 5.4 g of aluminum is exposed to a sulfuric acid solution if the hydrogen yield is 95% of the theoretical possible.

1. Under the action of sulfuric acid on aluminum, the reaction proceeds:

2Al + 3H2SO4 = Al2 (SO4) 3 + 3H2 ↑;

2.Calculate the chemical amount of aluminum:

n (Al) = m (Al): M (Al) = 5.4: 27 = 0.3 mol;

3. Determine the theoretical chemical amount of evolved hydrogen:

ntheor (H2) = n (Al) * 3: 2 = 0.2 mol;

4.calculate the practical amount of hydrogen:

npract (H2) = ntheor (H2) * ν = 0.3 * 0.95 = 0.285 mol;

5.find the volume of hydrogen:

V (H2) = npract (H2) * Vm = 0.285 * 22.4 = 6.384 l.

Answer: 6.384 l.