What volume of hydrogen will be released when 6.9 g of sodium interacts with hydrochloric acid?
| December 18, 2020 | education
2Na + 2HCl = 2NaCl + H2
Solution: m (Na) = 6.9 g, M (Na) = 23 g / mol, n (Na) = m / M = 6.9 / 23 = 0.3
2 mol Na – 1 mol H2
0.3 mol – x mol
n (H2) = 0.3 / 2 = 0.15 mol
V (H2) = n * Vm = 0.15 * 22.4 = 3.36 l
Answer: 3.36 L
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