What volume of hydrogen will be released when 6 g of beryllium is dissolved in hydrochloric acid?

1. The dissolution of beryllium in water is described by the reaction equation:

Be + 2H2O = Be (OH) 2 + H2 ↑;

2.Calculate the chemical amount of beryllium entering into the reaction:

n (Be) = m (Be): M (Be) = 6: 9 = 0.6667 mol;

3.the interaction of 1 mole of beryllium with water leads to the release of 1 mole of hydrogen, then the amount of hydrogen:

n (H2) = n (Be) = 0.6667 mol;

4.Set the volume of released hydrogen:

V (H2) = n (H2) * Vm = 0.6667 * 22.4 = 14.93 liters.

Answer: 14.93 liters.