What volume of hydrogen will be released when aluminum is dissolved in 43.8 g of 20% hydrochloric acid solution?

The reaction of aluminum with hydrochloric acid is described by the following chemical reaction equation.

Al + 3HCl = AlCl3 + 1.5 H2;

When 1 mol of aluminum is dissolved, 1.5 mol of hydrogen is released. This requires 3 mol of hydrochloric acid.

Determine the amount of the substance contained in 43.8 grams of a 20% hydrochloric acid solution.

M HCl = 1 + 35.5 = 36.5 grams / mol;

m HCl = 43.8 x 0.2 = 8.76 grams;

N HCl = 8.76 / 36.5 = 0.24 mol;

Reaction with 0.24 mol of hydrochloric acid with sufficient aluminum will result in 0.12 mol of hydrogen.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of hydrogen.

V H2 = 0.12 x 22.4 = 2.688 liters;