What volume of hydrogen will be released when aluminum reacts with 160 g of 15% sodium hydroxide solution?

univerkov | August 4, 2021 | education

1. Let’s compose the equation of the chemical reaction of substances.

2Al + 6H2O + 2NaOH = 2Na [Al (OH) 4] + 3H2.

2. Find the amount of reacted sodium hydroxide.

m (NaOH) = m (solution) * ω (NaOH) / 100% = 160 g * 15% / 100% = 24 g.

n (NaOH) = m (NaOH) / M (NaOH) = 24 g / 40 g / mol = 0.6 mol.

3. Based on the reaction equation, we find the amount and then the volume of the generated hydrogen.

n (H2) = n (NaOH) * 3/2 = 0.6 mol * 3/2 = 0.9 mol.

V (H2) = n (H2) * Vm = 0.9 mol * 22.4 l / mol = 20.16 l.

Answer: V (H2) = 20.16 liters.

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