What volume of hydrogen will be released when an excess of hydrochloric acid acts on aluminum

What volume of hydrogen will be released when an excess of hydrochloric acid acts on aluminum with a chemical amount of 0.200 mol?

Metallic aluminum interacts with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and hydrogen gas bubbles are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

N Al = 0.2 mol;

This will synthesize the same amount of salt.

The chemical amount of released hydrogen will be: 0.2 x 3/2 = 0.3 mol

Let’s find its volume.

To do this, multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 0.3 x 22.4 = 6.72 liters;