What volume of hydrogen will be released when an excess of zinc interacts with a solution

What volume of hydrogen will be released when an excess of zinc interacts with a solution of sulfuric acid weighing 196 g with a mass fraction of acid of 2%.

The interaction of zinc with sulfuric acid occurs in accordance with the following chemical reaction equation:

Zn + H2SO4 = ZnSO4 + H2;

When 1 mole of metal dissolves, 1 mole of hydrogen gas is released.

Find the amount of substance in 196 grams of 2% sulfuric acid solution

Its mass is equal to:

m H2SO4 = 196 x 0.02 = 3.92 grams;

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 3.92 / 98 = 0.04 mol;

0.04 mol of zinc will react with 0.04 mol of sulfuric acid. This will release 0.04 mol of hydrogen.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.04 x 22.4 = 0.896 liters;