What volume of hydrogen will be released when interacting with zinc 300 g of hydrochloric

What volume of hydrogen will be released when interacting with zinc 300 g of hydrochloric (chloride) acid solution with 20% HCL mass fraction

The reaction of hydrochloric acid with zinc proceeds according to the following equation.

Zn + 2HCl → ZnCl2 + H2;

Hydrochloric acid reacts with zinc in double quantities. In this case, 1 hydrogen molecule is formed from 2 acid molecules.

Let’s calculate the chemical amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 300 x 0.2 / 36.5 = 1.644 mol;

Knowing the volume of 1 mole of an ideal gas, we find the volume of hydrogen:

V H2 = 22.4 x 0.822 = 18.413 liters;