What volume of hydrogen will be released when magnesium reacts with an amount

What volume of hydrogen will be released when magnesium reacts with an amount of a substance of 0.75 mol with an excess of acetic acid?

The interaction of magnesium with acetic acid occurs in accordance with the following chemical reaction equation:

Mg + 2CH3COOH = Mg (CH3COO) 2 + H2;

When 0.75 metal dissolves, 0.75 mol of hydrogen gas is released.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.75 x 22.4 = 16.8 liters;