What volume of hydrogen will be released when sodium is dissolved in an amount of 2 mol in water?

The reaction of sodium with water occurs in accordance with the following chemical reaction equation:

Na + H2O = NaOH + ½ H2;

In accordance with it, when 1 mole of metal interacts with 1 mole of water, 0.5 mole of hydrogen gas is released.

Therefore, when reacting with 2 mol of sodium, 1 mol of hydrogen will be released.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be equal to:

V H2 = 1 x 22.4 = 22.4 liters;