What volume of hydrogen will be released when zinc is dissolved in 100 ml of 20%

What volume of hydrogen will be released when zinc is dissolved in 100 ml of 20% (by weight) hydrochloric acid solution (solution density ρ = 1.10 g / ml)

The interaction of zinc with any acid, for example with hydrogen chloride, occurs in accordance with the following chemical reaction equation:

Zn + 2HCl = ZnCl2 + H2;

Regardless of the type of acid, dissolving 1 mole of metal releases 1 mole of hydrogen gas. This requires 2 mol of hydrogen chloride.

Let’s find the mass of hydrogen chloride.

m HCl = 100 x 1.10 x 0.2 = 22 grams.

Let’s calculate the amount of the substance contained in 22 grams of hydrogen chloride.

To do this, we find the ratio of its weight to molar mass.

N HCl = 22 / (1 + 35.5) = 0.603 mol;

When reacting with 0.603 mol of hydrogen chloride, 0.3015 mol of hydrogen gas will be released.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.3015 x 22.4 = 6.75 liters;



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