What volume of nitric oxide 2 will be released during the interaction of 32 g nickel with dilute nitric acid?

According to the condition of the problem, we compose the reaction equation, select the coefficients:
3Ni + 8HNO3 = 2NO + 3Ni (NO3) 2 + 4H2O – redox reaction, nitric oxide (2) brown gas is released;
M (Ni) = 58.7 g / mol; M (NO) = 30 g / mol;
Let us determine the number of moles of nickel, if the mass is known:
Y (Ni) = m / M = 32 / 58.7 = 0.545 mol;
Let’s make the proportion:
0.545 mol (Ni) – X mol (NO);
-3 mol -2 mol hence, X mol (NO) = 0.545 * 2/3 = 0.363 mol;
Find the volume of nitric oxide:
V (NO) = 0.363 * 22.4 = 8.13 liters.
Answer: during the reaction, nitrogen oxide (2) with a volume of 8.13 liters is released.