What volume of nitric oxide (II) will be released during the catalytic oxidation of 12 liters of ammonia?

In this task you need to determine the volume of nitric oxide. First, you need to write down the equation of a chemical reaction.

4NH3 + 5O2 = 4NO + 6H2O.
Let’s determine the amount of ammonia substance.
n = V / Vm.
n = 12 / 22.4 = 0.54 mol.
Determine the amount of nitric oxide substance. Let’s make a proportion.
0.54 mol – x mol.
4 mol – 4 mol.
X = 0.54 * 4/4 = 0.54 mol.
Determine the volume of nitric oxide.
V = n * Vm = 0.54 * 22.4 = 12.1 liters.
This means that the volume of nitric oxide is 12.1 liters.
Answer: 12.1 liters.