What volume of oxygen is consumed for the combustion of methanol by the amount of substance 0.2 mol?

The oxidation reaction of methanol is described by the following chemical reaction equation.

CH3OH + 3/2 O2 = CO2 + 2H2O;

According to the coefficients of this equation, 1.5 oxygen molecules are required to oxidize 1 molecule of methanol. This synthesizes 1 molecule of carbon dioxide.

Let us calculate the amount of oxygen required for the oxidation of 0.2 mol of methanol.

The amount of oxygen will be.

N O2 = 0.2 x 1.5 = 0.3 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V O2 = 0.3 x 22.4 = 6.72 liters;