What volume of oxygen is required for complete combustion of 10 liters of acetylene containing

What volume of oxygen is required for complete combustion of 10 liters of acetylene containing 10 liters of impurities?

The oxidation reaction of acetylene with oxygen is described by the following chemical reaction equation:

2C2H2 + 5O2 = 4CO2 + 2H2O;

2 moles of acetylene are reacted with 5 moles of oxygen.

Let’s calculate the available chemical amount of the acetylene substance.

To do this, we divide the volume of gas by the volume of 1 mole of ideal gas. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

N C2H2 = 10 / 22.4 = 0.446 mol;

To burn such an amount of matter, you need to take 0.446 x 5/2 x 0.9 = 1 mole of oxygen.

Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V O2 = 1 x 22.4 = 22.4 liters;