What volume of oxygen is required for firing 0.2 mol of FeS 2 and what mass of iron (III) oxide and volume of sulfur

What volume of oxygen is required for firing 0.2 mol of FeS 2 and what mass of iron (III) oxide and volume of sulfur (IV) oxide will be obtained?

4FeS + 7O2 = 2Fe2O3 + 4SO2
n (Fes) = 0.2 mol
n (O2) = 0.35 mol
V (CO2) = 0.35 mol * 22.4 g / mol = 7, 84 l
or proportion
17.6 = x
352 = 156.8
x = 17.6 * 156.8 / 352 = 7.84 l



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