What volume of oxygen is required for the oxidation of ammonia according to the equation:

What volume of oxygen is required for the oxidation of ammonia according to the equation: 4NH3 + 5O2 – 4NO + 6H2O if the amount of ammonia is taken in the amount of 2 mol?

The reaction of catalytic oxidation of ammonia with oxygen is described by the following chemical equation:

4NH3 + 5O2 = 4NO + 6H2O;

N NH3 = 2 mol;

To oxidize such an amount of a substance, it is necessary to take (in accordance with the coefficients of the chemical equation) 2 x 5/4 = 2.5 mol of oxygen.

Let’s find the volume of oxygen.

To do this, multiply its amount by the volume of 1 mole of gas (assuming a volume of 22.4 liters).

V O2 = 2.5 x 22.4 = 56 liters;