What volume of oxygen measured can be obtained by decomposition of mercury (2) oxide with a mass of 100 g.

Given:
m (HgO) = 100 g

To find:
V (O2) -?

1) 2HgO => 2Hg + O2 ↑;
2) n (HgO) = m / M = 100/217 = 0.46 mol;
3) n (O2) = n (HgO) / 2 = 0.46 / 2 = 0.23 mol;
4) V (O2) = n * Vm = 0.23 * 22.4 = 5.2 liters.

Answer: The O2 volume is 5.2 liters.



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