What volume of oxygen O2 is needed for the reaction with aluminum Al

What volume of oxygen O2 is needed for the reaction with aluminum Al, the amount of substance is 0.5 mol. Find the mass of aluminum oxide Al2O3.

The aluminum combustion reaction is described by the following chemical reaction equation:

4Al + 3O2 = 2Al2O3;

To burn 0.5 mol of metal, 0.5 x 3/4 = 0.375 mol of oxygen is required.

Let’s calculate its volume.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V H2 = 0.375 x 22.4 = 8.4 liters;

When 0.5 mol of metal is burned, 0.5 / 2 = 0.25 mol of its oxide will be synthesized.

Let’s calculate its weight.

M Al2O3 = 27 x 2 + 16 x 3 = 102 grams / mol;

m Al2O3 = 102 x 0.25 = 25.5 grams / mol;