What volume of oxygen will be consumed during the combustion of 5 liters of a mixture of hydrogen sulfide

What volume of oxygen will be consumed during the combustion of 5 liters of a mixture of hydrogen sulfide and ammonia, if the volume fraction of hydrogen sulfide is 0.4.

4NH3 + 3O2 = 2N2 + 6H2O (1)
2H2S + 3O2 = 2SO2 + 2H2O (2)
Only 5 liters. The volume fraction of hydrogen sulfide = 0.4 hence its volume is 5 * 0.4 = 2 liters
v (o2) in (2) = 2 * 2: 2 * 3 = 3 liters
v (nh3) = 5-2 = 3 liters
v (o2) d (1) = 3: 4 * 3 = 2.25 liters
total oxygen volume = 2.25 + 3 = 5.25



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