What volume of oxygen will be obtained from the decomposition of 49 g of potassium chlorate?
| April 24, 2021 | education
Let us write the decomposition equation 2KClO₃ = 2KCl + 3O₂.
calculate the molecular weight of KClO₃ = 39.0983 + 35.45 + 15.999 * 3 = 122.5453 g / mol.
Let’s make the proportion:
49 g – X dm3
(2 * 122.5) g – (3 * 22.4) dm3
Let us express X = (49 * 3 * 22.4) / (2 * 122.5) = 13.94 dm3
Answer: VO₂ = 13.44 dm3
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