What volume of oxygen will be released during the decomposition of 120 g of berthollet salt (KClO3)?

univerkov | January 17, 2021 | education

Given:
m (KClO3) = 120 g
To find:
V (O2)
Decision:
2KClO3 = 2KCl + 3O2
n (KClO3) = m / M = 120 g / 122.5 g / mol = 1 mol
n (KClO3): n (O2) = 2: 3
n (O2) = 1 mol / 3 * 2 = 0.66 mol
V (O2) = n * Vm = 0.66 mol * 22.4 l / mol = 14.78 l
Answer: 14.78 L

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