What volume of oxygen will be released during the decomposition of 5 mol of potassium nitrate?
| November 27, 2020 | education
2 KNO3 = 2 KNO2 + O2
n (KNO3) / n (O2) = 2/1, therefore n (O2) = 2.5
V (O2) = 2.5 * 22.4 = 56 liters.
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