What volume of oxygen will be released during the decomposition of 72 g water?

The decomposition reaction of water is described by the following chemical equation:

H2O = H2 + 1/2 O2;

Let’s calculate the chemical amount of water for this, divide its weight by the weight of 1 mole of the substance.

M H2O = 2 + 16 = 18 grams / mol;

N H2O = 72/18 = 4 mol;

When this amount of water is decomposed, 4/2 = 2 mol of oxygen will be released.

Let’s define its volume.

To do this, multiply the amount of the substance by the volume of 1 mole of the substance (which is 22.4 liters).

V O2 = 2 x 22.4 = 44.8 liters;