What volume of sodium hydroxide solution with a concentration of 0.25 mol / l will be required to completely neutralize

| December 12, 2020 | education

What volume of sodium hydroxide solution with a concentration of 0.25 mol / l will be required to completely neutralize the combustion products of natural gas, consisting of 96% methane, 1% ethane, 2% hydrogen sulfide (by volume)?

First, we write down the reaction of combustion of all gases (reaction of interaction with oxygen). Then we find the number of moles for each gas, calculate the moles of combustion products interacting with alkali. Then we write down the neutralization equations and calculate.

Combustion reactions of all gases:
CH4 + 2O2 = CO2 + 2H2O
C2H6 + 7/2 O2 = 2CO2 + 3H2O
C3H8 = 5O2 = 3CO2 + 4H2O
We count the moles of CO2 and H20, we get 0.4 mol of CO2 and 20.3 mol of H2O.
Then:
2H2S = 3O2 = 2SO2 + 2H2O
We count the moles: 0.4 mole SO2 and 0.4 mole H2O

The neutralization reaction is written as follows:
2NaOH + CO2 = Na2CO3 + H2O
2NaOH + SO2 = Na2SO3 + H2O



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