What volume of sulfur dioxide will be released under the action of hydrochloric acid on 25.2 kg of sodium sulfite

univerkov | September 25, 2021 | education

Na2SO3 + 2HCl = 2NaCl + H2O + SO2.
The same number of moles of sulfur dioxide is released as the salt reacts. Thus, the volume of SO2 is equal to:
(25200: 126) mol * 22.4 L / mol = 4480 L.

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