What volume of sulfur dioxide will be released when 91.35 g of nitric acid interacts with sodium sulfite solution?
| November 20, 2020 | education
Let’s write the reaction equation: Na2SO3 + 2HNO3 = 2NaNO3 + SO2 + H2O
Let’s calculate the amount of nitric acid substance: 91.35 / 63 = 1.45 (mol)
According to the reaction equation, we see that the amount of sulfur dioxide is two times less than the amount of nitric acid.
Find the volume of sulfuric gas: 0.725 * 22.4 = 16.24 (l)
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