What volume of sulfur oxide (4) can be absorbed by a solution of barium hydroxide with an amount of 3 mol?

1. Let’s compose the equation of the reaction between barium hydroxide and sulfur oxide (IV).

Let us determine in what quantitative ratios the substances are.

1 mole of barium hydroxide accounts for 1 mole of sulfur oxide. This means that their amounts of matter will be the same.

Ba (OH) 2+ SO2 = BaSO3 + H2O.

n (Ba (OH) 2) = n (SO2) = 3 mol.

Let’s find the volume of SO2.

The volume is determined by the formula:

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 3 mol × 22.4 L / mol = 67.2 L.

Answer: 67.2 liters.