What volume of sulfuric acid solution (w = 88%, p = 1.8 g / cm3) should be taken

What volume of sulfuric acid solution (w = 88%, p = 1.8 g / cm3) should be taken to prepare a 300 cm3 solution of this acid with w = 0.4 (p = 1.3 cm3)?

Determine the weights of the components of the solution.

To do this, it is necessary to multiply their mass fraction by the weight of the solution.

Find the weight of pure sulfuric acid.

M pure acid = 300 x 0.4 x 1.3 = 156 grams;

In order to find the volume of a sulfuric acid solution with such an acid weight, it is necessary to divide this acid weight by its concentration and density.

The volume of the sulfuric acid solution will be:

V sulfuric acid solution = 156 / 0.88 / 1.8 = 98.45 ml;

The mass of water in the solution will be:

M water (solvent) = 300 x 0.6 x 1.3 = 234 grams;

Let’s check:

M solution = M acid + M water = 156 + 234 = 390 grams;