What volume will 0.71 g of chlorine take under normal conditions?

1 mole of ideal gas under normal (standard) conditions fills a volume equal to 22.4 liters.

Let’s calculate the amount of a substance that is in a given mass of a substance.

To do this, we divide its mass by molar mass.

M Cl2 = 35.5 x 2 = 71 grams / mol;

N Cl2 = 0.71 / 71 = 0.01 mol;

The gas volume will be:

V = 0.01 x 22.4 = 0.224 liters;