What volume will 96 g of so2 take under normal conditions?

Given:

m (SO2) = 96 g.

V (SO2) -?

Decision:

Find the volume of sulfur (IV) oxide SO2.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

n = m: M.

M (SO2) = 64 g / mol.

n = 96 g: 64 g / mol = 1.5 mol.

V = 1.5 mol × 22.4 L / mol = 33.6 L.

Answer: 33.6 liters.



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