What volume will a mixture of 0.5 mol nitrogen and 0.25 mol chlorine take?

univerkov | November 26, 2020 | education

For gases, the amount of substance is determined by the formula n = v / 22.4 (at n.u)
Then v = n * 22.4
For nitrogen v = 0.5 * 22.4 = 11.2 l
for chlorine v = 0.25 * 22.4 = 5.6 l
Adding the resulting volumes, we find out the volume of the mixture v = 11.2 + 5.6 = 16.8 l

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