What volume will be occupied by nitrogen oxide (|||) weighing 152 g.
Nitric oxide (III) has the gross formula N2O3. In its pure form, it exists at temperatures below -4 degrees in a solid state. Under standard conditions, it is a colorless poisonous gas. In a gaseous state under standard conditions, it decomposes into nitrogen oxide (II) and nitrogen oxide (IV).
To solve the problem, we first need to calculate the amount of substance of a given mass of gas, and then, through the molar volume, we determine the amount of moles of this gas.
Molar mass of N2O3 = 76 g / mol
N = m / M = 152/76 = 2 mol.
Molar volume Vm of any gas at normal conditions is 22.4 l / mol. If the problem does not specify other conditions, then we consider them normal.
V = N * Vm = 2 * 22.4 = 44.8 liters
Answer: The volume of nitric oxide (III) is 44.8 liters.