What volume will be occupied by the hydrogen released when dissolving zinc with

What volume will be occupied by the hydrogen released when dissolving zinc with a mass of 32.5 in hydrochloric acid with a mass of 54.75 g?

In accordance with the reaction equation, the molar amount of synthesized hydrogen will be equal to the amount of dissolved zinc:

Zn + 2HCl → ZnCl2 + H2;

Let’s find the molar amount of zinc.

M Zn = 65 grams / mol;

N Zn = 32.5 / 65 = 0.5 mol;

Let’s calculate the chemical amount of hydrochloric acid.

M HCl = 1 + 35.5 = 36.5 grams / mol;

N HCl = 54.75 / 36.5 = 1.5 mol;

The acid is taken in excess.

Let’s calculate the volume of 0.5 mol of hydrogen.

V H2 = 22.4 x 0.5 = 11.2 liters;