What volume will hydrogen take when interacting with 6.5 grams of zinc with an excess of hydrochloric acid?

The reaction is described by the following chemical equation:

Zn + 2HCl = ZnCl2 + H2;

Let’s find the chemical amount of zinc. To do this, divide its weight by the mass of 1 mole of metal.

N Zn = 6.5 / 65 = 0.1 mol;

With this amount of zinc, 0.1 x 2 = 0.2 mol of acid will react. This will synthesize 0.1 mol of hydrogen and 0.1 mol of zinc chloride. Let’s calculate the volume of hydrogen. To this end, we multiply the amount of substance by the volume of 1 mole of gas (which is 22.4 liters).

V H2 = 0.1 x 22.4 = 2.24 liters;

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