What volume will nitrogen take at 273 C, if at 0 C, its volume was 5 m ^ 3? The gas pressure is constant.
| September 25, 2021 | education
Initial data: T2 (final temperature of nitrogen) = 273 ºС = 273 + 273 К = 546 К; T1 (initial temperature of nitrogen) = 0 ºС = 273 K; V (volume occupied by nitrogen) = 5 m3; isobaric process (p = const).
For the isobaric process, the equality is true: V1 / T1 = V2 / T2, whence V2 = V1 * T2 / T1.
Let’s calculate: V2 = 5 * 546/273 = 10 m3.
Answer: After isobaric expansion, nitrogen will occupy a volume of 10 m3.
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